9t^2-60t+63=0

Solution for 9t^2-60t+63=0 equation:

9t^2-60t+63=0

a = 9; b = -60; c = +63;
Δ = b2-4ac
Δ = -602-4·9·63
Δ = 1332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1332}=\sqrt{36*37}=\sqrt{36}*\sqrt{37}=6\sqrt{37}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-6\sqrt{37}}{2*9}=\frac{60-6\sqrt{37}}{18}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+6\sqrt{37}}{2*9}=\frac{60+6\sqrt{37}}{18}
$